Deriving the vector parallelogram theorem eqation
Pythagoras theorem OBDΔ
OD²+DB² = OB²
OD = OA+AD
cosθ = AD sinθ = BD
AB AB
AD = ABcosθ BD = Asinθ
= Qcosθ = Qsinθ
OA = P
OD = P+Qcosθ BD = Qsinθ
OB² = R² = (P+Qcosθ)² + (Qsinθ)²
= p² + 2PQcosθ + Q²sin²θ + Q²cos²θ
= P² + 2PQcosθ + Q²(sin²θ + cos²θ)
= P² + 2PQcosθ + Q²
tanα = BD = Qsinθ
= OD = P+Qcosθ